IBPS SO Prelims Exam Model Paper 10

Given:
The perimeter of Rectangle = 144
Perimeter of Rectangle = 2 × perimeter of square
Formula:
Perimeter of rectangle = 2 (length + breadth)
Perimeter of square = 4 × side
Circumference of square = 2π × radius
Diagonal of square = √2 × side
Calculation:
Perimeter of rectangle = 2 × Perimeter of square
⇒ 144 = 2 × 4 × side
⇒ side = 18
So, Diagonal of square = √2 × 18 = 18√2
⇒ Circumference of circle = Area of square
⇒ 2πR = side × side
⇒ 2 × (

22

7

) × R = 18 × 18
⇒ R = 567/11
⇒ Diagonal of the square : Radius of circle
⇒ 18√ 2:

567

11

⇒ 22√2: 63
∴ Ratio between diagonal of square and radius of circle = 22√2 : 63