IBPS SO Prelims Exam Model Paper 1

Given:
The total area of four walls = 600 m2
The length of wall =

3

2

times of width
The height of room = 10 m
Formulae required:
The area of four walls = perimeter of floor × height
The perimeter of floor = 2 × (length + width)
Area of floor = length × width
Calculations:
Let the width of a wall be 'x'
The length of a wall =

3x

2

Area of four walls = 2 × (length + width) × height
⇒ 600 = 2 × (length + width) × height
⇒ 300 = (x +

3x

2

) × 10
⇒ 30 =

5x

2

⇒ x = 12 m
Hence, the width of floor = 12 m
The length of floor = 3 ×

12

2

⇒ 18 m
The Area of floor = 12 × 18
⇒ 216 m2
∴ The area of floor is 216 m2