IBPS SO Prelims Exam Model Paper 1

I. 2x2 – 17x + 36 = 0
⇒ 2x2 – 8x – 9x + 36 = 0
⇒ 2x(x – 4) – 9(x – 4) = 0
⇒ (x – 4) (2x – 9) = 0
Thus, x = 4 or

9

2

II. 2y2 – 19y + 45 = 0
⇒ 2y2 – 10y – 9y + 45 = 0
⇒ 2y(y – 5) – 9(y – 5) = 0
⇒ (2y – 9) (y – 5) = 0
Thus, y =

9

2

or 5So, when x = 4, for y =

9

2

, then x > y and when x = 4, for y = 5, then x < y
And when x = 9/2, for y =

9

2

, then x = y and when x =

9

2

, for y = 5, then x < y
∴ We can observe that x ≤ y