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Question : 68 of 200
Marks:
+1,
-0
Solution:
(2)1 I.x2+7x+12=0
⇒x2+4x+3x+12=0
⇒ x (x + 4) + 3 (x + 4) = 0
⇒ (x + 3) (x + 4) = 0
⇒ x = –3 or – 4
II. y2+6y+8=0
⇒ y2+4y+2y+8=0
⇒ y (y + 4) + 2 (y + 4) = 0
⇒ (y + 2) (y + 4) = 0
⇒y = –2 or –4
Clearly, x ≤ y
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