IBPS RRB Office Assistant 26 Sep 2015 Paper

(3) Speed of train = 63 kmph
= (

63×5

18

)

m

sec

.=17.5

m

sec

Let the length of train be xmetre.
When a train crosses a platform, the distance covered byit = length of platform and thetrain
∴17.5=

x+355

40

⇒x+355=17.5×40=700
⇒x=700−355=345 metre
Relative speed of train=(63+6) kmph.
=(

69×5

18

) m /sec.= (

115

6

) m / sec
∴ Required time
=(

345

115

×6 ) seconds
=18 seconds