IBPS RRB Office Assistant 2018 Paper

Let the total quantity of mixture = 100 L
Then, quantity of milk =100×

60

100

=60L
and quantity of water = 100 - 60 = 40 L
Let x units water mixed. According to the question,

40

100

=

60

100+x

⇒ 4000 + 40x = 6000
⇒ 40x = 2000
∴ x = 50
∴ Required percentage =

50

100

×100%=50%