IBPS PO Prelims Model Paper 3 with solutions

5 consecutive multiples of 4 = 4x, 4 (x + 1), 4 (x + 2), 4 (x + 3) and 4 (x + 4)
⇒ 4 [x + x + 1 + x + 2 + x + 3 + x + 4] = 100
⇒5x+10=

100

4

=25
⇒x=3
∴ Largest number = 4 (x + 4) = 4 × 7 = 28
For series S2,
Second lowest number = 28 – 6 = 22
∴ 4 consecutive even numbers are : 20, 22, 24, 26
Required average =

20+22+24+26

4

=

92

4

= 23