IBPS PO Prelims Model Paper 15

(3) Let the speed of current = x km/hr
And the speed of boat in still water = y km/hr
Therefore, rate of downstream = (y + x) km/hr and rate of upstream = (y – x) km/hr
According to given question ,

x

y+x

=

1

7

⇒ y=6x‌and‌

2.75

y−x

=

11

60

⇒ x = 3 and y = 18
Required distance = Rate of downstream × Time =

21×52

60

= 18.2 km