IBPS PO Prelims Model Paper 12

Let Mohan’s initial weight = 7x kg
Meera’s initial weight = 8x kg
Therefore,
7x + 8x = 120
⇒ x = 8
Mohan’s weight = 7 × 8 = 56 kg
Meera’s weight = 8 × 8 = 64 kg
Let Meera reduces by y kg. Thus,

56−6

64−y

=

5

6

⇒6(50)=5(64−y)
⇒300=320−5y
⇒y=4
Thus, Meera has reduced by 4 kg.