IBPS PO Prelims 2017 Solved Paper

Let d = 4x and h = 3x
Total surface area of right circular cylinder is 2pr (r + h)
Where r → radius
h → height
∴ 2π [2x(2x+3x)−

3x

2

(

3x]

2

+3x)] = 416 π
2[10x2–6.75x2] = 416
6.5x2 = 416
x2 = 64
x = ±8
∴ radius (r) = 16
height (h) = 24
∴ Circumference of base of cylinder = 2πr
= 32 π cm2