IBPS PO Mains 2018 Paper for online practice
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DIRECTIONS (Qs.98-100):
There are three quantities provided in the questions. You have to find out the values of the quantities and compare them according to the given codes as follows
@ ® >
& ⇒ <
* ⇒ >
$ ⇒ <
# ⇒ = (or relationship can’t be established)
Example :
Quantity I: 23 + 33 + 43
Quantity II: 62 × 22
Quantity III: 63 – 23 × 32
(a) @,$
(b) &, #
(c)$ , #
(d) &, *
(e) @, #
Quantity I < Quantity II = Quantity III
So, answer is (b)
There are three quantities provided in the questions. You have to find out the values of the quantities and compare them according to the given codes as follows
@ ® >
& ⇒ <
* ⇒ >
# ⇒ = (or relationship can’t be established)
Example :
Quantity I: 23 + 33 + 43
Quantity II: 62 × 22
Quantity III: 63 – 23 × 32
(a) @,
(b) &, #
(c)
(d) &, *
(e) @, #
Quantity I < Quantity II = Quantity III
So, answer is (b)
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Question : 100 of 155
Marks:
+1,
-0
Quantity I – In a question paper probability of a question not being answered by three students is 0.5, 0.4, 0.7 respectively. Find the probability that at most two students will solve the question.
Quantity II – Dipak have 5 black balls & 7 white balls, in his bag. If three balls are drawn at random from bag, then find probability of getting at least 1 black ball.
Quantity III – Nirmal speaks the truth 4 out of 5 times, and Puja speaks the truth 6 out of 7 times. What is the probability that they will contradict each other in stating the same fact?
Quantity II – Dipak have 5 black balls & 7 white balls, in his bag. If three balls are drawn at random from bag, then find probability of getting at least 1 black ball.
Quantity III – Nirmal speaks the truth 4 out of 5 times, and Puja speaks the truth 6 out of 7 times. What is the probability that they will contradict each other in stating the same fact?
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