IBPS PO Exam 2014 Solved Paper

I. 6x2 + 14x = 12
3x2 + 7x – 6 = 0
(x + 3) (3x – 2) = 0
x = −3,

2

3

II. 1 + 2y2 =

17

6

y
12y2 – 17y + 6 = 0
12y2 – 8y – 9y + 6 = 0
4y (3y – 2) – 3 (3y – 2) = 0
(3y – 2) (4y – 3) = 0
y =

2

3

,

3

4

Hence, x ≤ y