IBPS PO Exam 2014 Solved Paper

I. 2x2 + 5x + 1 = x2 + 2x – 1
x2 + 3x + 2 = 0
x2 + 2x + x + 2 = 0
x (x + 2) + 1 (x + 2) = 0
(x + 2) (x + 1) = 0
x = –2 , –1
II. 2y2 – 8y + 1 = –1
2y2 – 8y + 2 = 0
y2 – 4y + 1 = 0

+4±√16−4×1×1

2×1

= 2 ± √12 = 2 ± 2√3
Hence, y > x