IBPS Clerk Prelims Model Paper 8

Let initially there be 7 litres of mixture.
Amount of water = 2 litres
Amount of alcohol = 5 litres Let x litres of mixture be rep laced with water.
Quantity of water in 7 litres of mixture = 2 litres
Therefore,
Quantity of water in x litres of mixture =

2x

7

litres
Quantity of alcohol in 7 litres of mixture = 5 litres
Therefore,
Quantity of alcohol in x litres of mixture =

5x

7

litres
Quantity of water in new mixture is
⇒ (2−

2x

7

+x)
Quantity of alcohol in new mixture is
⇒ (5−

5x

7

)
According to the question, the new mixture contains water and alcohol in equal parts,

(5− 5x 7 )

2− 2x 7 +x

= 1
5−

5x

7

= 2 +

5x

7

3 =

10x

7

x = 2.1 litres
Hence, it is the required result.