IBPS Clerk Prelims Model Paper 23

Let Rex have z cars and Jagan have (30 – z) cars.
Price of Jagan’s cars = Rs. y
Price of Rex’s cars = Rs. x
xz = y(30 – z) … (1)
and x(30 – z) = 32
x =

32

(30−z)

... (2)
zy = 24.5
y =

24.5

z

... (3)
Putting the values of x and y in equation 1, we get

32

30−z

.z =

24.4

z

(30−z)
On solving, we get
z2 + 196z – 2940 = 0
Using quadratic formula,
z = 14 or −210
∴ z = 14 (neglecting negative value)
∴ Price of Rex’s cars = Rs. 2.0 lakh