IBPS Clerk Prelims Model Paper 21

I. 6x2 – 19x + 15 = 0
6x2 – 9x – 10x + 15 = 0
3x(2x – 3) – 5(2x – 3) = 0
(2x – 3) (3x – 5) = 0
x =

5

3

,

3

2

II. 10y2 – 29y + 21 = 0
10y2 – 15y – 14y + 21 = 0
5y(2y – 3) – 7(2y – 3) = 0
(2y – 3) (5y – 7) = 0
y =

3

2

,

7

5

Conclusions:
x = y =

3

2

;

7

5

<

3

2

,

5

3

⇒x≥y
Hence, this is the correct answer.