IBPS Clerk Prelims Model Paper 18

According to the given information
bcy g ax ⇒ bcy < ax ...(i)
cy α bz ⇒ cy = bz ...(ii)
and a2 γ bc ⇒ a2 < bc ...(iii)
From (ii), we get
c2y = bcz > a2z
[∴ bc > a2 from (iii)]
⇒ c2y > a2y
From (i), we get
ax > bcy I > a2y
[∴ bc > a2 from (iii)]
⇒ ax > a2y
⇒ x > ay
⇒ cx > acy
⇒ cx > abz [∴ cy = bz from (ii)]
⇒ cx ≠ abz
⇒ cx d abz.