IBPS Clerk Prelims Model Paper 16

A completes of whole work
= 20 ×

100

80

= 20 ×

5

4

= 25 days
Remaining work = 1 -

80

100

= 1 -

4

5

=

1

5

Let B complete whole work in t days
B’s 1 day work =

1

t

A’s 1 day work =

1

25

Both’s 1 day work =

1

t

+

1

25

Both’s 3 days work = 3(

1

t

+

1

25

)

1

5

= 3(

1

t

+

1

25

)

1

15

−

1

25

=

1

t

5−3

75

=

1

t

⇒ t =

75

2

= 37.5 days