IBPS Clerk Prelims Model Paper 12

Diagonal of Rectangle
AC = 3√41 cm
Length of Rectangle = x cm
∴ Let Breadth of Rectangle
BC =

4x

5

cm
In Δ ABC
∴Since AB2+BC2 = AC2
x2+(

4x

5

)2 = (3√41)2
x2+

16x2

25

= 9 × 41

25x2+16x2

25

= 9 × 41
41x2 = 9 × 41 × 25
x2 =

9×41×25

41

= 9 × 25
x = √9×25 = 15 cm
⇒ Perimeter of rectangle
= 2 (l + b)
= 2(x+

4x

5

)
=

18x

5

=

18×15

5

= 54 cm