IBPS Clerk Mains 2019 Paper

Let, original speed of car = 100 a km/hr
So, increased speed of car = 100a × 1.2
= 120 a km/hr
ATQ,
3600 / 100a−

3600

120a

=

50

60

36

a

−

30

a

=

5

6

6

a

=

5

6

5a = 36
a = 7.2
Original speed of car = 7.2×100
= 720 km/hr
Increased speed of car = 720×1.2=864
Car travel with its increased speed in 3 hrs. =864×3km.=2592 km