{\int_{0}^{1}\f(x)\dx=2 \and \int_{0}^{1}\f(x)\dx=-3 \then\int_{1}^{4}(3\f(x)+2)\dx=}

HCU MCA 2016 Paper

Question : 67 of 75

Marks: +1, -0

{∫↙{0}↖{1}\f(x)\dx=2 \and ∫↙{0}↖{1}\f(x)\dx=-3 \then∫↙{1}↖{4}(3\f(x)+2)\dx=}

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