HCU MCA 2016 Paper

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Question : 36 of 75

Marks: +1, -0

The equation of the locus of a point, which moves so that the sum of its distances from two given points (ae, 0) and (–ae, 0) is equal to 2a is;

$\x^2/\a^2+\y^2/\b^2=1$ where $\b^2=\a^2(1-\e^2)$
$\x^2/\b^2+\y^2/\a^2=1$ where $\b^2=\a^2(1-\e^2)$
$(\bx)^2+(\ay^2)=1$ where $\b^2=\a^2(1-\e^2)$
$(\ax)^2+(\by^2)=1$ where $\b^2=\a^2(1-\e^2)$

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