HCU MCA 2013 Paper

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Question : 70 of 75

Marks: +1, -0

\cos A + \cos B

can also be written as

2 $\cos { ( A + B ) }/ { 2 } \cos { ( A - B ) } /{ 2 }$
2 $\cos { ( A - B ) }/ { 2 } \sin { ( A - B ) } /{ 2 }$
2 $\cos { ( A + B ) }/ { 2 } \sin { ( A - B ) } /{ 2 }$
2 $\cos { ( A + B ) }/ { 2 } \sin { ( A - B ) } /{ 2 }$

Solution:

(a)

\cos A + \cos B=

2

\cos { ( A + B ) }/ { 2 } \cos { ( A - B ) } /{ 2 }

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