HCU MCA 2013 Paper

Question : 46 of 75

Marks: +1, -0

Consider the unit square formed by points in the plane; A(0, 0), B(1, 0),C (1,1) and D(0,1). Let P be an arbitrary point chosen in this unit square. Connect P to the points A and B. The probability that the points ABP form an obtuse traingle is

0.393
0.712
0.5
0.25

Validate

Solution:

If, we consider a point P inside the rectangle ABEF,then the triangle will be obtuse triangle.
∴ Required probability =

{\Area \of \rectangle \ABEF}/{\Area \of \square}

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\={1/2 ×1}/{1×1}=1/2=0.5

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