HCU MCA 2013 Paper

(a) Area of sector at one corner $=\frac{\mathrm{\pi }{\left(7\right)}^2}{4}$
$=\frac{22}{7}\times \frac{7^2}{4}$
$=\frac{154}{4}$
∴ Area of 4 sector = $\frac{154}{4}\times 4=154$
But area of given circular pond = 20 m${}^2$
∴Required ungrazed area
= Area of square - Area of 4 sector- Area of circular pond
= ${\left(14\right)}^2-154-20$
= 196 -174
= 22 m${}^2$