HCU MCA 2013 Paper

Question : 13 of 75

Marks: +1, -0

3 small pumps and a large pump are filling a tank. Each of the three small pumps works at

2/ 3

rd the rate of the large pump. In what fraction of the time that all 4 pumps working together will fill the tank in comparison to the time taken by the large pump alone?

$4/7$
$1/3$
$2/3$
$3/4$

Validate

Solution:

3/2×\t=3/2\t

∴ Three small pump fill the tank =

3/2\t×1/3=\t/2

∴ 4 pumps fill the tank =

\t/2+\t={3\t}/2

∴ Required fraction =

\t/({3\t}/2)={2/3

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