Haryana Police Constable Model Paper 6

Given:
A pump can fill a pot in 2 hours.
With leakage, the pot can be filled in $2\frac{1}{3}$ hours
Concept:
If a tap can fill a tank in x hours, then the tank filled by the tap in $1\mathrm{hour}=\frac{1}{\mathrm{x}}$ of the total tank.
Calculation:
Work done in 1 hour by the pump $=\frac{1}{2}$
Work done in 1 hour by leakage and pump $=\frac{3}{7}$
Work done by the leakage in 1 hour $=\left(\frac{1}{2}\right)\mathit{–}\left(\frac{3}{7}\right)$
$\Rightarrow \frac{\left(7\mathit{–}6\right)}{14}=\frac{1}{14}$
∴ The leakage can empty the pot in 14 hours.