Haryana Police Constable Model Paper 5

Question : 64 of 100

Marks: +1, -0

\If \x + \y = 10 \and \x^{2 }+ \y^{2} = 68, \then \find \xy

Solution:

As per the given data,
We know that

(x + \y)^{2} = \x^{2} + \y^{2} + 2\xy

(10)^{2} = 68 + 2\xy

100 - 68 = 2\xy

32 = 2\xy

\xy = 16

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