Haryana Police Constable Model Paper 4

Given:
We have to find the HCF of $\frac{9}{10},\frac{3}{25}$
Concept Used:
HCF of fraction = $\frac{\left(\mathrm{HCF}\mathrm{of}\mathrm{numerator}\right)}{\left(\mathrm{LCM}\mathrm{of}\mathrm{denominator}\right)}$
Calculation:
HCF of $\frac{9}{10},\frac{3}{25}$
⇒ $\frac{\mathrm{HCF}\left(9,3\right)}{\mathrm{LCM}\left(10,25\right)}$
HCF of numerators is 3
LCM of denominators is 50
Required HCF is $\frac{3}{50}$
∴ HCF of $\frac{9}{10},\frac{3}{25},\frac{6}{15},\frac{1}{25}\mathrm{is}\left(\frac{3}{50}\right).$