Haryana Police Constable Model Paper 3

Given:
A coin is tossed 3 times.
Formula used:
P (getting all heads) = $\frac{\left(\mathrm{Number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}\right)}{\left(\mathrm{Total}\mathrm{number}\mathrm{ofoutcomes}\right)}$
Calculation:
Total possible outcomes
⇒ (TTT), (TTH), (THT), (HTT), (THH), (HTH), (HHT), (HHH)
The total number of outcomes = 8.
Number of favorable outcomes = (HHH)
$\mathrm{P}\left(\mathrm{getting}\mathrm{all}\mathrm{heads}\right)=\frac{\left(\mathrm{Number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}\right)}{\left(\mathrm{Total}\mathrm{number}\mathrm{if}\mathrm{outcomes}\right)}$
⇒ P (getting all heads) = $\frac{1}{8}$
∴ The probability of getting all heads are $\frac{1}{8}$ .