Haryana Police Constable Model Paper 2

Formula used:
$\mathrm{P}\left(\mathrm{A}\right)=\frac{\mathrm{n}\left(\mathrm{E}\right)}{\mathrm{n}\left(\mathrm{S}\right)}$
where, n(E) → Required events, n(S) → Sample space
Calculation:
Let S be the sample space
S = 1, 2, 3, 4, 5, 6
n(S) = 6
Let E be the event of getting exact divisible by 2
E = 2, 4, 6
n(E) = 3
$\mathrm{P}\left(\mathrm{A}\right)=\frac{\mathrm{n}\left(\mathrm{E}\right)}{\mathrm{n}\left(\mathrm{S}\right)}$
⇒ P(A) = $\frac{3}{6}$
⇒ $\frac{1}{2}$
∴ The probability of getting exact divisible by 2 is $\frac{1}{2}$