If A=\left[\begin{array}{cc}2 & -4 \ -3 & 6]\end{array} then A^{-1}= \_\_\_\_ .

Correct Answer is : Does not exist

\frac{1}{24}\left[\begin{array}{cc}-2 & 4 \ 3 & -6]\end{array}

\frac{1}{24}\left[\begin{array}{cc}6 & 4 \ 3 & 2]\end{array}

\frac{1}{24}\left[\begin{array}{cc}-6 & 4 \ 3 & -2]\end{array}

GUJCET 2024 Math Paper (04)

Question : 23 of 40

Marks: +1, -0

If A=[

2	−4
−3	6

] then A−1= ____ .

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−2	4
3	−6

−6	4
3	−2