GUJCET 2023 Math Solved Paper

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Question : 21 of 40

Marks: +1, -0

Particular solution of the differential equation ‌

dy

dx

=−4xy2, Given that y=1, where x=0 is :

y=‌
1
2x2+1
x=‌
1
2y2+1
y=2x2+1
y=‌
x
2x2+1

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