\int \frac{\tan x}{\cos x( \sec x-1)( \sec x-2)} \dx=____________ +C

Correct Answer is : log| secx−2 secx−1|

\log {| \frac{ \sec x-2}{ \sec x-1} |}

\log {| \frac{ \sec x+2}{ \sec x-1} |}

\log {| {{\cosec} x+2}/{{\cosec} x-1} |}

\log {| \frac{\cos x+1}{\cos x-2} |}

GUJCET 2023 Math Solved Paper

Question : 12 of 40

Marks: +1, -0

∫‌

tan‌x

cos‌x( secx−1)( secx−2)

‌dx=____________ +C

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