\int(x+1)(x+3)(x+2)^7 d x=_____+C

Correct Answer is : (x+2)1010−(x+2)88

\frac{(x+2)^{10}}{10}+\frac{(x+2)^8}{8}

\frac{(x+2)^{10}}{10}-\frac{(x+2)^8}{8}

\frac{(x+3)^{10}}{10}-\frac{(x+3)^8}{8}

\frac{(x+3)^{10}}{10}+\frac{(x+3)^8}{8}

GUJCET 2022 Math Solved Paper

Question : 32 of 40

Marks: +1, -0

∫(x+1)(x+3)(x+2)7dx=_____+C

Go to Question:

Prev Question

Next Question