If A=[\table \cos \theta , \sin \theta ; -\sin \theta , \cos \theta] then A^3=

Correct Answer is : [cos3θsin3θ−sin3θcos3θ]

[\table -\cos 3 \theta , \sin 3 \theta ; \sin 3 \theta , \cos 3 \theta]

[\table \cos 3 \theta , -\sin 3 \theta ; -\sin 3 \theta , \cos 3 \theta]

[\table \cos 3 \theta , \sin 3 \theta ; -\sin 3 \theta , \cos 3 \theta]

[\table \cos 3 \theta , \sin 3 \theta ; -\cos 3 \theta , \sin 3 \theta]

GUJCET 2022 Math Solved Paper

Question : 13 of 40

Marks: +1, -0

If A=[

cos‌θ	sin‌θ
−sin‌θ	cos‌θ

] then A3=

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−cos‌3‌θ	sin‌3‌θ
sin‌3‌θ	cos‌3‌θ

cos‌3‌θ	−sin‌3‌θ
−sin‌3‌θ	cos‌3‌θ

cos‌3‌θ	sin‌3‌θ
−sin‌3‌θ	cos‌3‌θ

cos‌3‌θ	sin‌3‌θ
−cos‌3‌θ	sin‌3‌θ