GUJCET 2021 Math Solved Paper

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Question : 25 of 40

Marks: +1, -0

If f(x)=‌

1+x

1−x

;x≠1, then f(x)⋅f(y)=

f(‌
x+y
1−xy
)
f(x⋅y)
f(‌
x+y
1+xy
)
f(‌
1
1+xy
)

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