\int \frac{x^{5}+1}{x+1} d x= +C

Correct Answer is : 5∑n=1((−1)n+1⋅xnn)

\sum_{n=1}^{4}((-1)^{n+1} \cdot \frac{x^{n}}{n})

\sum_{n=1}^{5}((-1)^{n+1} \cdot \frac{x^{n}}{n})

\sum_{n=1}^{4}((-1)^{n} \cdot \frac{x^{n}}{n})

\sum_{n=1}^{5}((-1)^{n} \cdot \frac{x^{n}}{n})

GUJCET 2021 Math Solved Paper

Question : 1 of 40

Marks: +1, -0

∫‌

x5+1

x+1

dx= +C

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