GUJCET 2019 Math Solved Paper

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Question : 39 of 40

Marks: +1, -0

|

1+x	1	1
1+y	1+2y	1
1+z	1+z	1+3z

|= 10K xyz(3+

1

x

+

1

y

+

1

z

), then k = ________

(where‌xyz≠0;3+

1

x

+

1

y

+

1

z

≠0)

1
5
2
5
1

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