|\table \sin ^{2} \theta , \cos ^{2} \theta ; -\cos ^{2} \theta , \sin ^{2} \theta|=

Correct Answer is : 12(1+cos22θ)

\frac{1}{2}(1+\cos ^{2} 2 \theta)

\frac{1}{2} (1-\sin ^{2} 2 \theta )