A rod of 10 {\cm} length is moving perpendicular to uniform magnetic ficld of intensity 5 \times 10^{-1} {\Wh} \/ {\m}^2. If the acceleration of the {\rod} is 5 {\m} \/ { s}^2, then the tate of increasc of induced emf is

Correct Answer is : 2.5×10−1Vs−1

GUJCET 2015 Physics Solved Paper

Question : 18 of 40

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A rod of 10‌cm length is moving perpendicular to uniform magnetic ficld of intensity 5×10−1‌Wh∕m2. If the acceleration of the rod is 5m∕ s2, then the tate of increasc of induced emf is

25×10−4‌Vs
2.5×10−1Vs−1
20×10−1‌Vs
20×10−4Vs−1

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