The Earth's magnetic field at some place on magnetic equator of Earth is 0.5 \times 10^{-4} {\T}. Consider the radius of Earth at that place as 6400 {\km}. Then, magnetic dipole moment of the Earth is {\Am}^2 (\mu_0=4 \pi \times 10^{-7} {\TmA}^{-1})

GUJCET 2014 Physics Solved Paper

Question : 14 of 40

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The Earth's magnetic field at some place on magnetic equator of Earth is 0.5×10−4T. Consider the radius of Earth at that place as 6400‌km. Then, magnetic dipole moment of the Earth is Am2 (µ0=4π×10−7TmA−1)

1.05×1023
1.31×1023
1.15×1023
1.62×1023

Validate

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