GATE Mechanical Engineering (ME) 2020 Shift 2 Solved Paper

Question : 31 of 65

Marks: +1, -0

If a reversed Carnot cycle operates between the temperature limits of 27°C and –3°C, then the ratio of the COP of a refrigerator to that of a heat pump (COP of refrigerator/COP of heat pump) based on the cycle is ________ (round off to 2 decimal places)

Your Answer:

Validate

Solution:

Reversed correct cycle:

( {\COP})_{ {Ref}}=\;{ {T}_{ {L}}}/{ {T}_{ {H}}- {T}_{ {L}}}

=\;{270}/{300-270}

( {\COP})_{ {Ref}}=9

Since

( {COP})_{ {Ref}}+1=( {\COP})_{ {H} . {P}}

( {\COP})_{ {H} . P}=9+1=10

\;{ {\COP} \;\text " of refrigerator "\;}/{\;\text " COP of Heat pump "\;}=\;{9}/{10}

=0.9

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