GATE Mechanical Engineering (ME) 2020 Shift 1 Solved Paper

Question : 46 of 65

Marks: +1, -0

The following data applies to basic shaft system:
tolerance for hole

=0.002 {mm}

tolerance for shaft

=0.001 {mm}

allowance

=0.003 {mm}

basic size

=50 {mm}

.
The maximum hole size is ____ mm (round off to 3 decimal places)

Solution:

Tolerance of hole

=0.002 {mm}

Tolerance of shaft

=0.001 {mm}

allowance

=0.003 {mm} ⇒

minimum
basic size

=50 {mm}

Max hole size

=50+0.003+0.002

=50.005 {mm}

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