GATE Mechanical Engineering (ME) 2020 Shift 1 Solved Paper

Question : 44 of 65

Marks: +1, -0

In a turning process using orthogonal tool geometry, a chip length of

100 {mm}

is obtained for an uncut chip length of

250 {mm}

.

The cutting conditions are: cutting speed

=30 {m} \/ {min}

, rake angle

=20^{∘} .

The shear plane angle is degrees (round off to one decimal place).

Solution:

r=\;{I_{c}}/{I}=\;{100}/{250}=0.4

Shear angle,

\tan φ=\;{r \cos α}/{1-r \sin α}

=\;{0.4 \cos (20^{∘})}/{1-0.4 \sin (20^{∘})}

ϕ=23.53

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