GATE Mechanical Engineering (ME) 2020 Shift 1 Solved Paper

Question : 41 of 65

Marks: +1, -0

A strip of thickness

40 {mm}

is to be rolled to a thickness of

20 {mm}

using a two-high mill having rolls of diameter

200 {mm}

. Coefficient of friction and arc length in

{mm}

, respectively are

Solution:

∆ {h}=µ^{2} {R}

40-20=µ^{2} × 100

µ^{2}=\;{20}/{100} ≈ 0.45

µ=0.45

1-\;{∆ {h}}/{ {D}}=\cos α ⇒ \cos α=1-\;{20}/{200}

{a}=0.451

\;\text " Arc length "\;= {Ra}

\;\; =100 × 0.451

Arc length

45.1 {mm}

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