GATE Mechanical Engineering (ME) 2020 Shift 1 Solved Paper

Question : 32 of 65

Marks: +1, -0

A flywheel is attached to an engine to keep its rotational speed between

100 {rad} {/} {s}

and 110

{rad} {/} {s}

. If the energy fluctuation in the flywheel between these two speeds is A.05 kJ then he moment of inertia of the flywheel is __________

{kg} ⋅ {m}^{2}

(round off to 2 decimal places).

Solution:

ω_{\max }=110 {rad} {/} {s}

ω_{\min }=100 {rad} {/} {s}

∆ {E}= {A} .05 {kJ}=1050 {J}

{I}=?

∆ {E}={ }_{2} {I}(ω^{2}{ }_{\max }-ω_{\min }^{2})

1050=\;{1}/{2} {I}(110^{2}-100^{2})

{I}=1

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