GATE Mechanical Engineering (ME) 2019 Shift 2 Solved Paper

Question : 64 of 65

Marks: +1, -0

A through hole is drilled in an aluminum alloy plate of

15 {mm}

thickness with a drill bit of diameter

10 {mm}

, at a feed of

0.25 {mm} {/} {rev}

and a spindle speed of

1200 {rpm}

. If the specific energy required for cutting this material is

0.7 {N} ⋅ {m} {/} {mm}^{3}

, the power required for drilling is _____________ W (round off to two decimal places).

Solution:

MRR

=\;{π d^{2}}/{4} ×

feed

\times

rev per sec

=\;{π(10)^{2}}/{4} × 0.25 × \;{1200}/{60}=125 π {\mm}^{3}

Specific energy

=0.7 {\Nm} {/} {\mm}^{3}

So, power required for drilling

=0.7 × 125 π=274.89 {W}

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