GATE Mechanical Engineering (ME) 2019 Shift 1 Solved Paper

Question : 49 of 65

Marks: +1, -0

A circular shaft having diameter

65.00_{-0.05}^{+0.01} {mm}

is manufactured by turning process. A

50 µ {m}

thick coating of TiN is deposited on the shaft. Allowed variation in TiN film thickness is

± 5 µ {m}

. The minimum hole diameter (in

{mm}

) to just provide clearance fit is

Solution:

For clearance fit, shaft maximum possible diameter should be less than bore inner diameter.

\Dia_{\min }=Max(65.00_{-0.05}^{+0.01})+2 × Max(0.05_{-0.005}^{+0005})

\text " Dia "_{\min }=65+0.01+2 ×(0.05+0.005)

\text " Dia "_{\min }=65.12

Go to Question:

Prev Question

Next Question