GATE Mechanical Engineering (ME) 2018 Shift 2 Solved Paper

Question : 50 of 65

Marks: +1, -0

A bar of circular cross section is clamped at ends

{P}

and

{Q}

as shown in the figure. A torsional moment

T=150 {Nm}

is applied at a distance of

100 {mm}

from end

{P}

. The torsional reactions

(T_{p}, T_{Q})

{Nm}

at the ends

{P}

and

{Q}

respectively are (All dimensions are in min)

Solution:

Since,

{G}

and are constant for bar,

T_{1} L_{1}=T_{2} L_{2}

T_{1} ⋅ 100=T_{2} .200

T_{1}=2 T_{2}

And,

T_{1}+T_{2}=T

Hence,

T_{1}=100 {Nm}

and

T_{2}=50 {Nm}

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